B

Step 1: Understand the concept of excess pressure in liquid drops. The excess pressure inside a drop is given by the formula derived from the Young-Laplace equation: $$ ext{P} = \frac{2\gamma}{r}$$ where P is the excess pressure, \gamma is the surface tension of the liquid, and r is the radius of the drop.
Step 2: Analyze the equation. From the formula, we can see that the excess pressure is inversely proportional to the radius of the drop:

• If the radius (r) is small, the excess pressure (P) is large.
• If the radius (r) is large, the excess pressure (P) is small.

Therefore, a smaller drop will have a greater excess pressure compared to a larger drop.
Step 3: Conclude based on the calculated relationships: Since the small drop has a smaller radius, it experiences more excess pressure than the big drop.
Therefore, the correct option is: B - More in the small drop.